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(3x-5)+2(3x+1)=45
We move all terms to the left:
(3x-5)+2(3x+1)-(45)=0
We multiply parentheses
(3x-5)+6x+2-45=0
We get rid of parentheses
3x+6x-5+2-45=0
We add all the numbers together, and all the variables
9x-48=0
We move all terms containing x to the left, all other terms to the right
9x=48
x=48/9
x=5+1/3
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