(3x-5)-3=(31+2x)

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Solution for (3x-5)-3=(31+2x) equation: 



(3x-5)-3=(31+2x)

We move all terms to the left:

(3x-5)-3-((31+2x))=0

We add all the numbers together, and all the variables

(3x-5)-((2x+31))-3=0

We get rid of parentheses

3x-((2x+31))-5-3=0



We calculate terms in parentheses: -((2x+31)), so:

(2x+31)

We get rid of parentheses

2x+31

Back to the equation:

-(2x+31)



We add all the numbers together, and all the variables

3x-(2x+31)-8=0

We get rid of parentheses

3x-2x-31-8=0

We add all the numbers together, and all the variables

x-39=0

We move all terms containing x to the left, all other terms to the right

x=39

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