(3x-5)/(12)+x=(3x+5)/(3)+3

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Solution for (3x-5)/(12)+x=(3x+5)/(3)+3 equation: 



(3x-5)/(12)+x=(3x+5)/(3)+3

We move all terms to the left:

(3x-5)/(12)+x-((3x+5)/(3)+3)=0

We add all the numbers together, and all the variables

x+(3x-5)/12-((3x+5)/3+3)=0

We calculate fractions


x+(9x-15)/()+(-((3x+5)*12)/()=0



We calculate terms in parentheses: +(-((3x+5)*12)/(), so:

-((3x+5)*12)/(

We multiply all the terms by the denominator


-((3x+5)*12)



We calculate terms in parentheses: -((3x+5)*12), so:

(3x+5)*12

We multiply parentheses

36x+60

Back to the equation:

-(36x+60)



We get rid of parentheses

-36x-60

Back to the equation:

+(-36x-60)



We get rid of parentheses

x+(9x-15)/()-36x-60=0

We multiply all the terms by the denominator


x*()+(9x-15)-36x*()-60*()=0

We add all the numbers together, and all the variables

x*()+(9x-15)-36x*()=0

We get rid of parentheses

x*()+9x-36x*()-15=0

We add all the numbers together, and all the variables

9x+x*()-36x*()-15=0

We move all terms containing x to the left, all other terms to the right

9x+x*()-36x*()=15

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