(3x-5)/(2x-4)=3

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Solution for (3x-5)/(2x-4)=3 equation: 



(3x-5)/(2x-4)=3

We move all terms to the left:

(3x-5)/(2x-4)-(3)=0



Domain of the equation: (2x-4)!=0

We move all terms containing x to the left, all other terms to the right

2x!=4

x!=4/2

x!=2

x∈R



We multiply all the terms by the denominator


(3x-5)-3*(2x-4)=0

We multiply parentheses

(3x-5)-6x+12=0

We get rid of parentheses

3x-6x-5+12=0

We add all the numbers together, and all the variables

-3x+7=0

We move all terms containing x to the left, all other terms to the right

-3x=-7

x=-7/-3

x=2+1/3

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