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(3x-5)/(x+1)=2/7
We move all terms to the left:
(3x-5)/(x+1)-(2/7)=0
Domain of the equation: (x+1)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
x!=-1
x∈R
(3x-5)/(x+1)-(+2/7)=0
We get rid of parentheses
(3x-5)/(x+1)-2/7=0
We calculate fractions
(21x-35)/(7x+7)+(-2x-2)/(7x+7)=0
We multiply all the terms by the denominator
(21x-35)+(-2x-2)=0
We get rid of parentheses
21x-2x-35-2=0
We add all the numbers together, and all the variables
19x-37=0
We move all terms containing x to the left, all other terms to the right
19x=37
x=37/19
x=1+18/19
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