(3x-5)/25+x=(3x+5)/5-1

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Solution for (3x-5)/25+x=(3x+5)/5-1 equation: 



(3x-5)/25+x=(3x+5)/5-1

We move all terms to the left:

(3x-5)/25+x-((3x+5)/5-1)=0

We add all the numbers together, and all the variables

x+(3x-5)/25-((3x+5)/5-1)=0

We calculate fractions


x+(15x-25)/()+(-((3x+5)*25)/()=0



We calculate terms in parentheses: +(-((3x+5)*25)/(), so:

-((3x+5)*25)/(

We multiply all the terms by the denominator


-((3x+5)*25)



We calculate terms in parentheses: -((3x+5)*25), so:

(3x+5)*25

We multiply parentheses

75x+125

Back to the equation:

-(75x+125)



We get rid of parentheses

-75x-125

Back to the equation:

+(-75x-125)



We get rid of parentheses

x+(15x-25)/()-75x-125=0

We multiply all the terms by the denominator


x*()+(15x-25)-75x*()-125*()=0

We add all the numbers together, and all the variables

x*()+(15x-25)-75x*()=0

We get rid of parentheses

x*()+15x-75x*()-25=0

We add all the numbers together, and all the variables

15x+x*()-75x*()-25=0

We move all terms containing x to the left, all other terms to the right

15x+x*()-75x*()=25

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