(3x-5)/2=(4x-1)/4

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Solution for (3x-5)/2=(4x-1)/4 equation: 



(3x-5)/2=(4x-1)/4

We move all terms to the left:

(3x-5)/2-((4x-1)/4)=0

We calculate fractions


3x/()+(-((4x-1)*2)/()=0



We calculate terms in parentheses: +(-((4x-1)*2)/(), so:

-((4x-1)*2)/(

We multiply all the terms by the denominator


-((4x-1)*2)



We calculate terms in parentheses: -((4x-1)*2), so:

(4x-1)*2

We multiply parentheses

8x-2

Back to the equation:

-(8x-2)



We get rid of parentheses

-8x+2

Back to the equation:

+(-8x+2)



We get rid of parentheses

3x/()-8x+2=0

We multiply all the terms by the denominator


3x-8x*()+2*()=0

We add all the numbers together, and all the variables

3x-8x*()=0

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