(3x-5)/5=(2x-7)/3

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Solution for (3x-5)/5=(2x-7)/3 equation: 



(3x-5)/5=(2x-7)/3

We move all terms to the left:

(3x-5)/5-((2x-7)/3)=0

We calculate fractions


3x/()+(-((2x-7)*5)/()=0



We calculate terms in parentheses: +(-((2x-7)*5)/(), so:

-((2x-7)*5)/(

We multiply all the terms by the denominator


-((2x-7)*5)



We calculate terms in parentheses: -((2x-7)*5), so:

(2x-7)*5

We multiply parentheses

10x-35

Back to the equation:

-(10x-35)



We get rid of parentheses

-10x+35

Back to the equation:

+(-10x+35)



We get rid of parentheses

3x/()-10x+35=0

We multiply all the terms by the denominator


3x-10x*()+35*()=0

We add all the numbers together, and all the variables

3x-10x*()=0

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