(3x-5)2+7(3x-5)+12=0

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Solution for (3x-5)2+7(3x-5)+12=0 equation: 



(3x-5)2+7(3x-5)+12=0

We multiply parentheses

6x+21x-10-35+12=0

We add all the numbers together, and all the variables

27x-33=0

We move all terms containing x to the left, all other terms to the right

27x=33

x=33/27

x=1+2/9

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