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(3x-5)=(x+1)
We move all terms to the left:
(3x-5)-((x+1))=0
We get rid of parentheses
3x-((x+1))-5=0
We calculate terms in parentheses: -((x+1)), so:We get rid of parentheses
(x+1)
We get rid of parentheses
x+1
Back to the equation:
-(x+1)
3x-x-1-5=0
We add all the numbers together, and all the variables
2x-6=0
We move all terms containing x to the left, all other terms to the right
2x=6
x=6/2
x=3
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