(3x-5)=7(2x+3)

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Solution for (3x-5)=7(2x+3) equation:



(3x-5)=7(2x+3)
We move all terms to the left:
(3x-5)-(7(2x+3))=0
We get rid of parentheses
3x-(7(2x+3))-5=0
We calculate terms in parentheses: -(7(2x+3)), so:
7(2x+3)
We multiply parentheses
14x+21
Back to the equation:
-(14x+21)
We get rid of parentheses
3x-14x-21-5=0
We add all the numbers together, and all the variables
-11x-26=0
We move all terms containing x to the left, all other terms to the right
-11x=26
x=26/-11
x=-2+4/11

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