(3x-6)(2x+14)=360

Solution for (3x-6)(2x+14)=360 equation:

(3x-6)(2x+14)=360

We move all terms to the left:

(3x-6)(2x+14)-(360)=0

We multiply parentheses ..

(+6x^2+42x-12x-84)-360=0

We get rid of parentheses

6x^2+42x-12x-84-360=0

We add all the numbers together, and all the variables

6x^2+30x-444=0

a = 6; b = 30; c = -444;
Δ = b2-4ac
Δ = 302-4·6·(-444)
Δ = 11556
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{11556}=\sqrt{36*321}=\sqrt{36}*\sqrt{321}=6\sqrt{321}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-6\sqrt{321}}{2*6}=\frac{-30-6\sqrt{321}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+6\sqrt{321}}{2*6}=\frac{-30+6\sqrt{321}}{12}
$