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(3x-6)(6x+2)=0
We multiply parentheses ..
(+18x^2+6x-36x-12)=0
We get rid of parentheses
18x^2+6x-36x-12=0
We add all the numbers together, and all the variables
18x^2-30x-12=0
a = 18; b = -30; c = -12;
Δ = b2-4ac
Δ = -302-4·18·(-12)
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1764}=42$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-42}{2*18}=\frac{-12}{36} =-1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+42}{2*18}=\frac{72}{36} =2 $
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