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(3x-6)(6x-5)=0
We multiply parentheses ..
(+18x^2-15x-36x+30)=0
We get rid of parentheses
18x^2-15x-36x+30=0
We add all the numbers together, and all the variables
18x^2-51x+30=0
a = 18; b = -51; c = +30;
Δ = b2-4ac
Δ = -512-4·18·30
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{441}=21$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-51)-21}{2*18}=\frac{30}{36} =5/6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-51)+21}{2*18}=\frac{72}{36} =2 $
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