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(3x-6)(9x+3)=0
We multiply parentheses ..
(+27x^2+9x-54x-18)=0
We get rid of parentheses
27x^2+9x-54x-18=0
We add all the numbers together, and all the variables
27x^2-45x-18=0
a = 27; b = -45; c = -18;
Δ = b2-4ac
Δ = -452-4·27·(-18)
Δ = 3969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3969}=63$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-63}{2*27}=\frac{-18}{54} =-1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+63}{2*27}=\frac{108}{54} =2 $
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