(3x-6)+(2x)=48

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Solution for (3x-6)+(2x)=48 equation: 



(3x-6)+(2x)=48

We move all terms to the left:

(3x-6)+(2x)-(48)=0

We add all the numbers together, and all the variables

2x+(3x-6)-48=0

We get rid of parentheses

2x+3x-6-48=0

We add all the numbers together, and all the variables

5x-54=0

We move all terms containing x to the left, all other terms to the right

5x=54

x=54/5

x=10+4/5

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