(3x-6)+(2x-8)+(x+10)+x=360

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Solution for (3x-6)+(2x-8)+(x+10)+x=360 equation: 



(3x-6)+(2x-8)+(x+10)+x=360

We move all terms to the left:

(3x-6)+(2x-8)+(x+10)+x-(360)=0

We add all the numbers together, and all the variables

x+(3x-6)+(2x-8)+(x+10)-360=0

We get rid of parentheses

x+3x+2x+x-6-8+10-360=0

We add all the numbers together, and all the variables

7x-364=0

We move all terms containing x to the left, all other terms to the right

7x=364

x=364/7

x=52

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