(3x-6)+1=(2x-8)+(x+13)

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Solution for (3x-6)+1=(2x-8)+(x+13) equation:


Simplifying
(3x + -6) + 1 = (2x + -8) + (x + 13)

Reorder the terms:
(-6 + 3x) + 1 = (2x + -8) + (x + 13)

Remove parenthesis around (-6 + 3x)
-6 + 3x + 1 = (2x + -8) + (x + 13)

Reorder the terms:
-6 + 1 + 3x = (2x + -8) + (x + 13)

Combine like terms: -6 + 1 = -5
-5 + 3x = (2x + -8) + (x + 13)

Reorder the terms:
-5 + 3x = (-8 + 2x) + (x + 13)

Remove parenthesis around (-8 + 2x)
-5 + 3x = -8 + 2x + (x + 13)

Reorder the terms:
-5 + 3x = -8 + 2x + (13 + x)

Remove parenthesis around (13 + x)
-5 + 3x = -8 + 2x + 13 + x

Reorder the terms:
-5 + 3x = -8 + 13 + 2x + x

Combine like terms: -8 + 13 = 5
-5 + 3x = 5 + 2x + x

Combine like terms: 2x + x = 3x
-5 + 3x = 5 + 3x

Add '-3x' to each side of the equation.
-5 + 3x + -3x = 5 + 3x + -3x

Combine like terms: 3x + -3x = 0
-5 + 0 = 5 + 3x + -3x
-5 = 5 + 3x + -3x

Combine like terms: 3x + -3x = 0
-5 = 5 + 0
-5 = 5

Solving
-5 = 5

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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