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(3x-6)/(3)=(2-4x)(/2)
We move all terms to the left:
(3x-6)/(3)-((2-4x)(/2))=0
We add all the numbers together, and all the variables
(3x-6)/3-((-4x+2)(+/2))=0
We multiply parentheses ..
-((-4x^2+2*/2))+(3x-6)/3=0
We calculate fractions
(-((-4x^2+2**3)/()+3x/()=0
We calculate terms in parentheses: +(-((-4x^2+2**3)/()+3x/(), so:
-((-4x^2+2**3)/()+3x/(
We can not solve this equation
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