(3x-6)/3=(2-4x)/2

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Solution for (3x-6)/3=(2-4x)/2 equation:



(3x-6)/3=(2-4x)/2
We move all terms to the left:
(3x-6)/3-((2-4x)/2)=0
We add all the numbers together, and all the variables
(3x-6)/3-((-4x+2)/2)=0
We calculate fractions
3x/()+(-((-4x+2)*3)/()=0
We calculate terms in parentheses: +(-((-4x+2)*3)/(), so:
-((-4x+2)*3)/(
We multiply all the terms by the denominator
-((-4x+2)*3)
We calculate terms in parentheses: -((-4x+2)*3), so:
(-4x+2)*3
We multiply parentheses
-12x+6
Back to the equation:
-(-12x+6)
We get rid of parentheses
12x-6
Back to the equation:
+(12x-6)
We get rid of parentheses
3x/()+12x-6=0
We multiply all the terms by the denominator
3x+12x*()-6*()=0
We add all the numbers together, and all the variables
3x+12x*()=0

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