(3x-6)/3=(2x+20)/2

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Solution for (3x-6)/3=(2x+20)/2 equation: 



(3x-6)/3=(2x+20)/2

We move all terms to the left:

(3x-6)/3-((2x+20)/2)=0

We calculate fractions


3x/()+(-((2x+20)*3)/()=0



We calculate terms in parentheses: +(-((2x+20)*3)/(), so:

-((2x+20)*3)/(

We multiply all the terms by the denominator


-((2x+20)*3)



We calculate terms in parentheses: -((2x+20)*3), so:

(2x+20)*3

We multiply parentheses

6x+60

Back to the equation:

-(6x+60)



We get rid of parentheses

-6x-60

Back to the equation:

+(-6x-60)



We get rid of parentheses

3x/()-6x-60=0

We multiply all the terms by the denominator


3x-6x*()-60*()=0

We add all the numbers together, and all the variables

3x-6x*()=0

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