(3x-6)/5=(2x+5)/10+(x-4)/2

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Solution for (3x-6)/5=(2x+5)/10+(x-4)/2 equation: 


x in (-oo:+oo)

(3*x-6)/5 = (2*x+5)/10+(x-4)/2 // - (2*x+5)/10+(x-4)/2

(3*x-6)/5-((2*x+5)/10)-((x-4)/2) = 0

(3*x-6)/5+(-1*(2*x+5))/10+(-1*(x-4))/2 = 0

(2*10*(3*x-6))/(2*5*10)+(-1*2*5*(2*x+5))/(2*5*10)+(-1*5*10*(x-4))/(2*5*10) = 0

2*10*(3*x-6)-1*2*5*(2*x+5)-1*5*10*(x-4) = 0

40*x-50*x-170+200 = 0

30-10*x = 0

(30-10*x)/(2*5*10) = 0

(30-10*x)/(2*5*10) = 0 // * 2*5*10

30-10*x = 0

30-10*x = 0 // - 30

-10*x = -30 // : -10

x = -30/(-10)

x = 3

x = 3

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