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(3x-6/12x-24)(x+3)=0
Domain of the equation: 12x-24)(x+3)!=0We multiply parentheses ..
x∈R
(+3x^2+9x-6x^2-18x-24x-72)=0
We get rid of parentheses
3x^2-6x^2+9x-18x-24x-72=0
We add all the numbers together, and all the variables
-3x^2-33x-72=0
a = -3; b = -33; c = -72;
Δ = b2-4ac
Δ = -332-4·(-3)·(-72)
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-15}{2*-3}=\frac{18}{-6} =-3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+15}{2*-3}=\frac{48}{-6} =-8 $
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