(3x-63)(4-8x)=0

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Solution for (3x-63)(4-8x)=0 equation:



(3x-63)(4-8x)=0
We add all the numbers together, and all the variables
(3x-63)(-8x+4)=0
We multiply parentheses ..
(-24x^2+12x+504x-252)=0
We get rid of parentheses
-24x^2+12x+504x-252=0
We add all the numbers together, and all the variables
-24x^2+516x-252=0
a = -24; b = 516; c = -252;
Δ = b2-4ac
Δ = 5162-4·(-24)·(-252)
Δ = 242064
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{242064}=492$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(516)-492}{2*-24}=\frac{-1008}{-48} =+21 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(516)+492}{2*-24}=\frac{-24}{-48} =1/2 $

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