(3x-63)+(2x+2)=x

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Solution for (3x-63)+(2x+2)=x equation: 



(3x-63)+(2x+2)=x

We move all terms to the left:

(3x-63)+(2x+2)-(x)=0

We add all the numbers together, and all the variables

-1x+(3x-63)+(2x+2)=0

We get rid of parentheses

-1x+3x+2x-63+2=0

We add all the numbers together, and all the variables

4x-61=0

We move all terms containing x to the left, all other terms to the right

4x=61

x=61/4

x=15+1/4

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