(3x-7)(2x-5)=5x-29x

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Solution for (3x-7)(2x-5)=5x-29x equation: 



(3x-7)(2x-5)=5x-29x

We move all terms to the left:

(3x-7)(2x-5)-(5x-29x)=0

We add all the numbers together, and all the variables

(3x-7)(2x-5)-(-24x)=0

We get rid of parentheses

(3x-7)(2x-5)+24x=0

We multiply parentheses ..

(+6x^2-15x-14x+35)+24x=0

We get rid of parentheses

6x^2-15x-14x+24x+35=0

We add all the numbers together, and all the variables

6x^2-5x+35=0

a = 6; b = -5; c = +35;
Δ = b2-4ac
Δ = -52-4·6·35
Δ = -815
Delta is less than zero, so there is no solution for the equation

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