(3x-7)(4x-3)=(6x-4)(2x-5)

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Solution for (3x-7)(4x-3)=(6x-4)(2x-5) equation: 



(3x-7)(4x-3)=(6x-4)(2x-5)

We move all terms to the left:

(3x-7)(4x-3)-((6x-4)(2x-5))=0

We multiply parentheses ..

(+12x^2-9x-28x+21)-((6x-4)(2x-5))=0



We calculate terms in parentheses: -((6x-4)(2x-5)), so:

(6x-4)(2x-5)

We multiply parentheses ..

(+12x^2-30x-8x+20)

We get rid of parentheses

12x^2-30x-8x+20

We add all the numbers together, and all the variables

12x^2-38x+20

Back to the equation:

-(12x^2-38x+20)



We get rid of parentheses

12x^2-12x^2-9x-28x+38x+21-20=0

We add all the numbers together, and all the variables

x+1=0

We move all terms containing x to the left, all other terms to the right

x=-1

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