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(3x-7)(5+7x)=0
We add all the numbers together, and all the variables
(3x-7)(7x+5)=0
We multiply parentheses ..
(+21x^2+15x-49x-35)=0
We get rid of parentheses
21x^2+15x-49x-35=0
We add all the numbers together, and all the variables
21x^2-34x-35=0
a = 21; b = -34; c = -35;
Δ = b2-4ac
Δ = -342-4·21·(-35)
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4096}=64$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-34)-64}{2*21}=\frac{-30}{42} =-5/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-34)+64}{2*21}=\frac{98}{42} =2+1/3 $
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