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(3x-7)(5x+3)=0
We multiply parentheses ..
(+15x^2+9x-35x-21)=0
We get rid of parentheses
15x^2+9x-35x-21=0
We add all the numbers together, and all the variables
15x^2-26x-21=0
a = 15; b = -26; c = -21;
Δ = b2-4ac
Δ = -262-4·15·(-21)
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1936}=44$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-44}{2*15}=\frac{-18}{30} =-3/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+44}{2*15}=\frac{70}{30} =2+1/3 $
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