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(3x-7)(7x-4)=0
We multiply parentheses ..
(+21x^2-12x-49x+28)=0
We get rid of parentheses
21x^2-12x-49x+28=0
We add all the numbers together, and all the variables
21x^2-61x+28=0
a = 21; b = -61; c = +28;
Δ = b2-4ac
Δ = -612-4·21·28
Δ = 1369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1369}=37$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-61)-37}{2*21}=\frac{24}{42} =4/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-61)+37}{2*21}=\frac{98}{42} =2+1/3 $
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