(3x-7)+(2x+2)=3(2x-10)

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Solution for (3x-7)+(2x+2)=3(2x-10) equation: 



(3x-7)+(2x+2)=3(2x-10)

We move all terms to the left:

(3x-7)+(2x+2)-(3(2x-10))=0

We get rid of parentheses

3x+2x-(3(2x-10))-7+2=0



We calculate terms in parentheses: -(3(2x-10)), so:

3(2x-10)

We multiply parentheses

6x-30

Back to the equation:

-(6x-30)



We add all the numbers together, and all the variables

5x-(6x-30)-5=0

We get rid of parentheses

5x-6x+30-5=0

We add all the numbers together, and all the variables

-1x+25=0

We move all terms containing x to the left, all other terms to the right

-x=-25

x=-25/-1

x=+25

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