(3x-7)+40=18

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Solution for (3x-7)+40=18 equation: 



(3x-7)+40=18

We move all terms to the left:

(3x-7)+40-(18)=0

We add all the numbers together, and all the variables

(3x-7)+22=0

We get rid of parentheses

3x-7+22=0

We add all the numbers together, and all the variables

3x+15=0

We move all terms containing x to the left, all other terms to the right

3x=-15

x=-15/3

x=-5

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