(3x-7)-5(x-4)=21

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Solution for (3x-7)-5(x-4)=21 equation: 



(3x-7)-5(x-4)=21

We move all terms to the left:

(3x-7)-5(x-4)-(21)=0

We multiply parentheses

(3x-7)-5x+20-21=0

We get rid of parentheses

3x-5x-7+20-21=0

We add all the numbers together, and all the variables

-2x-8=0

We move all terms containing x to the left, all other terms to the right

-2x=8

x=8/-2

x=-4

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