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(3x-7)/(3x+3)=2/3
We move all terms to the left:
(3x-7)/(3x+3)-(2/3)=0
Domain of the equation: (3x+3)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
3x!=-3
x!=-3/3
x!=-1
x∈R
(3x-7)/(3x+3)-(+2/3)=0
We get rid of parentheses
(3x-7)/(3x+3)-2/3=0
We calculate fractions
(9x-21)/(9x+9)+(-6x-6)/(9x+9)=0
We multiply all the terms by the denominator
(9x-21)+(-6x-6)=0
We get rid of parentheses
9x-6x-21-6=0
We add all the numbers together, and all the variables
3x-27=0
We move all terms containing x to the left, all other terms to the right
3x=27
x=27/3
x=9
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