(3x-7)/(x+4)=2

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Solution for (3x-7)/(x+4)=2 equation: 



(3x-7)/(x+4)=2

We move all terms to the left:

(3x-7)/(x+4)-(2)=0



Domain of the equation: (x+4)!=0

We move all terms containing x to the left, all other terms to the right

x!=-4

x∈R



We multiply all the terms by the denominator


(3x-7)-2*(x+4)=0

We multiply parentheses

(3x-7)-2x-8=0

We get rid of parentheses

3x-2x-7-8=0

We add all the numbers together, and all the variables

x-15=0

We move all terms containing x to the left, all other terms to the right

x=15

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