(3x-7)/10-x/5=x/10+4

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Solution for (3x-7)/10-x/5=x/10+4 equation: 


x in (-oo:+oo)

(3*x-7)/10-(x/5) = x/10+4 // - x/10+4

(3*x-7)/10-(x/5)-(x/10)-4 = 0

(3*x-7)/10-x/5-x/10-4 = 0

(5*(3*x-7))/(5*10)+(10*(-x))/(5*10)+(5*(-x))/(5*10)+(-4*5*10)/(5*10) = 0

5*(3*x-7)+10*(-x)+5*(-x)-4*5*10 = 0

5*x-5*x-200-35 = 0

-200-35 = 0

-235 = 0

-235/(5*10) = 0

-235/(5*10) = 0 // * 5*10

-235 = 0

x belongs to the empty set

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