(3x-7)/12=(1/6(2x-3))-(x-1)/8

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Solution for (3x-7)/12=(1/6(2x-3))-(x-1)/8 equation: 


x in (-oo:+oo)

(3*x-7)/12 = (1/6)*(2*x-3)-((x-1)/8) // - (1/6)*(2*x-3)-((x-1)/8)

(3*x-7)/12-((1/6)*(2*x-3))+(x-1)/8 = 0

(3*x-7)/12+(-1/6)*(2*x-3)+(x-1)/8 = 0

(3*x-7)/12-1/6*(2*x-3)+(x-1)/8 = 0

(8*(3*x-7))/(8*12)+(-1/6*8*12*(2*x-3))/(8*12)+(12*(x-1))/(8*12) = 0

8*(3*x-7)-1/6*8*12*(2*x-3)+12*(x-1) = 0

12*x-8*x-12-8 = 0

4*x-20 = 0

(4*x-20)/(8*12) = 0

(4*x-20)/(8*12) = 0 // * 8*12

4*x-20 = 0

4*x-20 = 0 // + 20

4*x = 20 // : 4

x = 20/4

x = 5

x = 5

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