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(3x-7)6x+143x-7=4
We move all terms to the left:
(3x-7)6x+143x-7-(4)=0
We add all the numbers together, and all the variables
143x+(3x-7)6x-11=0
We multiply parentheses
18x^2+143x-42x-11=0
We add all the numbers together, and all the variables
18x^2+101x-11=0
a = 18; b = 101; c = -11;
Δ = b2-4ac
Δ = 1012-4·18·(-11)
Δ = 10993
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(101)-\sqrt{10993}}{2*18}=\frac{-101-\sqrt{10993}}{36} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(101)+\sqrt{10993}}{2*18}=\frac{-101+\sqrt{10993}}{36} $
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