(3x-8)(x+3)=3x2-2x

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Solution for (3x-8)(x+3)=3x2-2x equation: 



(3x-8)(x+3)=3x^2-2x

We move all terms to the left:

(3x-8)(x+3)-(3x^2-2x)=0

We get rid of parentheses

-3x^2+(3x-8)(x+3)+2x=0

We multiply parentheses ..

-3x^2+(+3x^2+9x-8x-24)+2x=0

We get rid of parentheses

-3x^2+3x^2+9x-8x+2x-24=0

We add all the numbers together, and all the variables

3x-24=0

We move all terms containing x to the left, all other terms to the right

3x=24

x=24/3

x=8

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