(3x-8)+(x+12)=x

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Solution for (3x-8)+(x+12)=x equation: 



(3x-8)+(x+12)=x

We move all terms to the left:

(3x-8)+(x+12)-(x)=0

We add all the numbers together, and all the variables

-1x+(3x-8)+(x+12)=0

We get rid of parentheses

-1x+3x+x-8+12=0

We add all the numbers together, and all the variables

3x+4=0

We move all terms containing x to the left, all other terms to the right

3x=-4

x=-4/3

x=-1+1/3

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