(3x-8)/(4x+4)=9/28

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Solution for (3x-8)/(4x+4)=9/28 equation: 



(3x-8)/(4x+4)=9/28

We move all terms to the left:

(3x-8)/(4x+4)-(9/28)=0



Domain of the equation: (4x+4)!=0

We move all terms containing x to the left, all other terms to the right

4x!=-4

x!=-4/4

x!=-1

x∈R



We add all the numbers together, and all the variables

(3x-8)/(4x+4)-(+9/28)=0

We get rid of parentheses

(3x-8)/(4x+4)-9/28=0

We calculate fractions


(84x-224)/(112x+112)+(-36x-36)/(112x+112)=0

We multiply all the terms by the denominator


(84x-224)+(-36x-36)=0

We get rid of parentheses

84x-36x-224-36=0

We add all the numbers together, and all the variables

48x-260=0

We move all terms containing x to the left, all other terms to the right

48x=260

x=260/48

x=5+5/12

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