(3x-8)/4=(2x-7)/3

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Solution for (3x-8)/4=(2x-7)/3 equation: 



(3x-8)/4=(2x-7)/3

We move all terms to the left:

(3x-8)/4-((2x-7)/3)=0

We calculate fractions


3x/()+(-((2x-7)*4)/()=0



We calculate terms in parentheses: +(-((2x-7)*4)/(), so:

-((2x-7)*4)/(

We multiply all the terms by the denominator


-((2x-7)*4)



We calculate terms in parentheses: -((2x-7)*4), so:

(2x-7)*4

We multiply parentheses

8x-28

Back to the equation:

-(8x-28)



We get rid of parentheses

-8x+28

Back to the equation:

+(-8x+28)



We get rid of parentheses

3x/()-8x+28=0

We multiply all the terms by the denominator


3x-8x*()+28*()=0

We add all the numbers together, and all the variables

3x-8x*()=0

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