(3x-8)=2(7x+4)

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Solution for (3x-8)=2(7x+4) equation: 



(3x-8)=2(7x+4)

We move all terms to the left:

(3x-8)-(2(7x+4))=0

We get rid of parentheses

3x-(2(7x+4))-8=0



We calculate terms in parentheses: -(2(7x+4)), so:

2(7x+4)

We multiply parentheses

14x+8

Back to the equation:

-(14x+8)



We get rid of parentheses

3x-14x-8-8=0

We add all the numbers together, and all the variables

-11x-16=0

We move all terms containing x to the left, all other terms to the right

-11x=16

x=16/-11

x=-1+5/11

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