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(3x-9)(8x+2)=0
We multiply parentheses ..
(+24x^2+6x-72x-18)=0
We get rid of parentheses
24x^2+6x-72x-18=0
We add all the numbers together, and all the variables
24x^2-66x-18=0
a = 24; b = -66; c = -18;
Δ = b2-4ac
Δ = -662-4·24·(-18)
Δ = 6084
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6084}=78$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-66)-78}{2*24}=\frac{-12}{48} =-1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-66)+78}{2*24}=\frac{144}{48} =3 $
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