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(3x-9)(x+15)+90=180
We move all terms to the left:
(3x-9)(x+15)+90-(180)=0
We add all the numbers together, and all the variables
(3x-9)(x+15)-90=0
We multiply parentheses ..
(+3x^2+45x-9x-135)-90=0
We get rid of parentheses
3x^2+45x-9x-135-90=0
We add all the numbers together, and all the variables
3x^2+36x-225=0
a = 3; b = 36; c = -225;
Δ = b2-4ac
Δ = 362-4·3·(-225)
Δ = 3996
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3996}=\sqrt{36*111}=\sqrt{36}*\sqrt{111}=6\sqrt{111}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-6\sqrt{111}}{2*3}=\frac{-36-6\sqrt{111}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+6\sqrt{111}}{2*3}=\frac{-36+6\sqrt{111}}{6} $
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