(3x-9/x-4)-(2x+2/x+3)

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Solution for (3x-9/x-4)-(2x+2/x+3) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

3*x-(2*x)-(9/x)-(2/x)-4-3 = 0

3*x-2*x-9*x^-1-2*x^-1-4-3 = 0

1*x^1-11*x^-1-7*x^0 = 0

(1*x^2-7*x^1-11*x^0)/(x^1) = 0 // * x^2

x^1*(1*x^2-7*x^1-11*x^0) = 0

x^1

x^2-7*x-11 = 0

x^2-7*x-11 = 0

DELTA = (-7)^2-(-11*1*4)

DELTA = 93

DELTA > 0

x = (93^(1/2)+7)/(1*2) or x = (7-93^(1/2))/(1*2)

x = (93^(1/2)+7)/2 or x = (7-93^(1/2))/2

x in { (7-93^(1/2))/2, (93^(1/2)+7)/2} 

x in { (7-93^(1/2))/2, (93^(1/2)+7)/2 }

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