(3x/2)+(1/4)(x-2)=10

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Solution for (3x/2)+(1/4)(x-2)=10 equation: 


x in (-oo:+oo)

(1/4)*(x-2)+(3*x)/2 = 10 // - 10

(1/4)*(x-2)+(3*x)/2-10 = 0

1/4*(x-2)+(3*x)/2-10 = 0

(1/4*2*(x-2))/2+(3*x)/2+(-10*2)/2 = 0

1/4*2*(x-2)+3*x-10*2 = 0

7/2*x-20-1 = 0

7/2*x-21 = 0

(7/2*x-21)/2 = 0

(7/2*x-21)/2 = 0 // * 2

7/2*x-21 = 0

7/2*x-21 = 0 // + 21

7/2*x = 21 // : 7/2

x = 21/7/2

x = 6

x = 6

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