(3x/2)+4x=18+x

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Solution for (3x/2)+4x=18+x equation:



(3x/2)+4x=18+x
We move all terms to the left:
(3x/2)+4x-(18+x)=0
We add all the numbers together, and all the variables
(+3x/2)+4x-(x+18)=0
We add all the numbers together, and all the variables
4x+(+3x/2)-(x+18)=0
We get rid of parentheses
4x+3x/2-x-18=0
We multiply all the terms by the denominator
4x*2+3x-x*2-18*2=0
We add all the numbers together, and all the variables
3x+4x*2-x*2-36=0
Wy multiply elements
3x+8x-2x-36=0
We add all the numbers together, and all the variables
9x-36=0
We move all terms containing x to the left, all other terms to the right
9x=36
x=36/9
x=4

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