(3x/2)+x-(7x/5)=(3/10)(x-11)

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Solution for (3x/2)+x-(7x/5)=(3/10)(x-11) equation: 



(3x/2)+x-(7x/5)=(3/10)(x-11)

We move all terms to the left:

(3x/2)+x-(7x/5)-((3/10)(x-11))=0



Domain of the equation: 10)(x-11))!=0

x∈R



We add all the numbers together, and all the variables

(+3x/2)+x-(+7x/5)-((+3/10)(x-11))=0

We add all the numbers together, and all the variables

x+(+3x/2)-(+7x/5)-((+3/10)(x-11))=0

We get rid of parentheses

x+3x/2-7x/5-((+3/10)(x-11))=0

We multiply parentheses ..

-((+3x^2+3/10*-11))+x+3x/2-7x/5=0

We calculate fractions


(-((+3x^2+3*2*5)/()+30x^2/()+(-70x^2)/()+x=0

We can not solve this equation

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