(3x/2)+x=120

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Solution for (3x/2)+x=120 equation:



(3x/2)+x=120
We move all terms to the left:
(3x/2)+x-(120)=0
We add all the numbers together, and all the variables
(+3x/2)+x-120=0
We add all the numbers together, and all the variables
x+(+3x/2)-120=0
We get rid of parentheses
x+3x/2-120=0
We multiply all the terms by the denominator
x*2+3x-120*2=0
We add all the numbers together, and all the variables
3x+x*2-240=0
Wy multiply elements
3x+2x-240=0
We add all the numbers together, and all the variables
5x-240=0
We move all terms containing x to the left, all other terms to the right
5x=240
x=240/5
x=48

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